Question

solve radical 3sq.6x-9=3

Answer 1

so we have (6x-9)^(1/3)=3 correct?

Answer 2

to get rid of 1/3 power raise both sides to the 3rd power

Answer 3

6x-9=3^3

Answer 4

no 3cubed 6x-9=3

Answer 5

?

Answer 6

use that equation thing below this box

Answer 7

3\sqrt{6x-9}=3\]

Answer 8

\[\sqrt{(6x-9)^3}=3\]

Answer 9

is that right?

Answer 10

3 is index instead of 3rd power

Answer 11

\[\sqrt[3]{6x-9}=3\]

Answer 12

\[3\sqrt{6x-9}=3\]

Answer 13

oh 3 times that okay

Answer 14

sorry I am new at this

Answer 15

its k solve for the sqrt thing first

Answer 16

divide both sides by 3

Answer 17

(6x-9)^(1/2)=1

Answer 18

to get rid of the sqrt square both sides

Answer 19

I don't get it why do we divide both sides by 3

Answer 20

We are trying to solve for x.

Answer 21

okay

Answer 22

first step to get x by itself is to divide by that 3 since that sqrt is being multiplied by that 3

Answer 23

to undo multiplication by a number you divide by it

Answer 24

okay

Answer 25

so we have 6x-9=1

Answer 26

okay

Answer 27

+9 to both sides giving 6x=10

Answer 28

okay

Answer 29

divide 6 on both sides ( remember to undo multiplication u divide)

Answer 30

x=10/6=5/3

Answer 31

Don't forget to check your work

Answer 32

5/3 is my answer

Answer 33

how do I do that

Answer 34

so you said x=5/3. go back to your original problem and where there is a x plug in 5/3

Answer 35

lets see if we get the same thing on both sides and if we do that means it is a solution

Answer 36

3*(6*5/3-9)^(1/2)=3(10-9)^(1/2)=3(1)^(1/2)=3*1=3 since the left side = the right side that means we have x=5/3 is a solution

Answer 37

okay i wrote it down thank you

Answer 38

no problem