Question

functions f(x)= sq.40x and g(x)= sq. 10x
a) (f+g)=
b)(f-g)=
c)(fg)=
d)(f/g)=

Answer 1

think f(x) as f and g(x) as g
a. (f+g)= sq.40x+sq10x then solve and you get 3sq10x b/c 2 is a perfect sq you can pull it out of 4. Then you will have 2sq10x+sq10x=3sq10x
So, b. sq40x-sq10x same as in part a 2sq10x-sq10x=sq10x
c. sq40x*10x=20x

d. sq40x/sr10x=2