What is the probability of throwing two fair dice and
getting a total which is greater than or equal to 8?

Question

What is the probability of throwing two fair dice and				
getting a total which is greater than or equal to 8?

anonymous · Answer

The total possible outcomes for throwing any two dice:  
(6 choose 1) * (6 choose 1) 

Cases where we have 8 or more:

One die is a 4, and the other die is 4, 5, or 6.
or
One die is a 3, and the other die is 5, or 6.
or
One die is a 2 and the other die is a 6.

So the odds of having this outcome is

$$\left( 3 + 2 + 1 \right)\div36 = 1:6$$