Question

please help me..... how do i simplify (sqrt(3)-i)^9

Answer 1

\[(\sqrt{3}-i)^{9}= [(\sqrt{3}-i)^{3}]^{3}\]
\[(\sqrt{3}-i)^{3}= (\sqrt{3}-i)(\sqrt{3}-i)(\sqrt{3}-i)\]

Answer 2

I wonder how to simplify it... :(

Answer 3

First, u calculate\[(\sqrt{3}-i)^{2}=(\sqrt{3}-i)(\sqrt{3}-1)\]
then, u use what u got to calculate \[(\sqrt{3}-i)^{2}(\sqrt{3}-i)= (\sqrt{3}-i)^{3}\]
let \[A=(\sqrt{3}-i)^{3}\]
\[(\sqrt{3}-i)^{9}= [(\sqrt{3}-i)^{3}]^{3} = A ^{3}\]

Answer 4

remember that i*i=-1