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Mathematics 23 Online
OpenStudy (anonymous):

(In(sin^4x))^2

OpenStudy (anonymous):

= 2ln*sin^4(x). I don't know what the question is.

OpenStudy (anonymous):

Not quite, the expression within the log has to be raised to a power for it to shift over - it ends up being 16 * ln^2(sin(x)) after simplification...but we do need to know what the question is even asking..:P

OpenStudy (anonymous):

(2ln*sin^4(x))(1/(sin^4x))(4 sin^3 x)(cos x)

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