Question

find the derivative of:

y=e^x/x^2-x

Answer 1

quotient rule

Answer 2

what is the alue of g(x), i know it cant be 0.

Answer 3

value not alue

Answer 4

by using uv' - vu'/v^2....
e^x( 2x-1) - (x^2-x.e^x)/ (x^2-x)^2
=e^x2x-e^x - e^x.x^2+e^x.x/ (x^2-x)^2

Answer 5

omg, im so dumb, im sorry didnt realize g(x) = x^2-x

Answer 6

im sorry

Answer 7

thank you so much for your help!

Answer 8

let f(x)= \[e^x\]
let g(x)= \[x^2-x\]

now, use this formula \[{f \prime x [g(x)]- [f(x)]g \prime x}/[g(x)]^2\]

Answer 9

yes sorry, i just forgot that g=x^2-x .. thank you tho

Answer 10

np