Question

1= (7/a-3) - (42/a^2-9)

Answer 1

(7/a-3)-(42/a^2-9)
here
a^2-9=(a+3)(a-3)
take L.C.M
answer = (7a-21)/(a^2-9)

Answer 2

what do you do with the 1 in front of the equation

Answer 3

wait a mint

Answer 4

ok
write a^2-9=(a+3)(a-3)
multiply both side of equation by (a+3)(a-3)
at the equation becomes a^2-7a+21=0

Answer 5

Oh ok! I gotcha, thank you so much!!