A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 93m long and 72m wide.
Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 93m  long and 72m wide.
Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

anonymous · Answer

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anonymous · Answer

The rectangle is:
$$93 \cdot 72  m^2$$
Both semicirckes equals on semicircle with the area:
$$A_{circle}= r^2 \cdot \pi = (36 m)^2 \cdot \pi$$

All together is:

$$6696 + 4069,66= 10765,44$$

anonymous · Answer

*equals a circle

Don't know how to correct a posting.