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verify this trig identity and scan in if possible plz... need all help i can get... :)
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\[(tanxcotx/cosx)=secx \]
tan x=sin x/cos x and cot x = 1/tan x= cos x/sin x so, (tan x)(cot x)=(sin x)(cos x)/(cos x)(sin x)= 1 therefore i/cos x= sec x
Here's another approach. Since we know tanxcotx = 1. \[\left( tanxcotx\right)/cosx =secx\] \[1/cosx = secx \]
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