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Mathematics 15 Online
OpenStudy (anonymous):

(tan+cot)^2 = sec^2 + csc^2 (working from one side only to get the other side)

OpenStudy (anonymous):

\[=\tan^{2}+2tanxcotx+\cot^{2}\] \[=\tan^{2}+\cot^{2}+2\] \[=\tan^{2}+1+cot^{2}+1\]

OpenStudy (anonymous):

You should remember your Pythagoras identities.

OpenStudy (anonymous):

Yes I do, thanks sooo much!

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