charles opened the trunk and found $6750 in $1 bills and $10 bills. If there were 150 more ones than tens, how many of each kind were there?

Question

anonymous · Answer

Let$$n_1, n_{10}$$be the number of $1 and $10 bills respectively.  You know that$$n_1=n_{10}+150$$since the number of 1s is 150 more than the number of 10s.

You also know$$6750=n_1$1+n_{10}$10$$that is$$6750=n_1+10n_{10}$$

anonymous · Answer

Sub. the expression for n_1 into the second equation to find$$6750=(n_{10}+150)+10n_{10}=11n_{10}+150$$

anonymous · Answer

Then$$n_{10}=\frac{6750-150}{11}=600$$

anonymous · Answer

There are 600 $10 bills.  So the number of $1s is,$$n_1=6750-10 \times 600=750$$

anonymous · Answer

thanks so very much

anonymous · Answer

No probs :)