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Dividing Rationale Expressions Simplify: 4x^2/16x^3 (four x square divided by sixteen x cube)
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\[\frac{4x^2}{16x^3}=\frac{4 \times x \times x}{4 \times 4 \times x \times x \times x}\]
You have common factors of 4 and (x times x) above and below. You can cancel these out to get\[\frac{1}{4x}\]
16x^2y/24xy^3
2x/3y^2 is this correct?
\[\frac{16x^2y}{24xy^3}=\frac{2x}{3y^2}\]Yes, that's correct.
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