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Mathematics 15 Online
OpenStudy (anonymous):

can anyone help me solve this? Find the slope of a line tangent to the given curve at the point P by finding the limit of the slopes of the secant lines PQ as Q approaches P. y = 5x^2-5; P is ( 3, 40); let Q have x-values of 2.5, 2.9, 2.99, 2.999

OpenStudy (anonymous):

Find the y-values for Q with those respective x-values. Then find the slopes for PQ by using (y1 - y2)/(x1 - x2)

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