Question

factor out the trinomial.
h=-2tsquared+87t+90

Answer 1

if h=ax^2+bx+c
then \[h=(-b/2a)\pm [(\sqrt{b ^{2}-4ac})/2a]\]

Answer 2

huh? well i know from there what you do is \[-(2t ^{2}-87-90)\] then you multiply 90 and 2t squared which gives you -180 then what you have to do is think what times what vies me 180 but also when u add/subtract them it gives you 87 and i dont know those two number