Question

From a boat on the lake, the angle of elevation to the top of a cliff is 16°36'. If the base
of the cliff is 1892 feet from the boat, how high is the cliff (to the nearest foot)

Answer 1

\[\tan(16^o32')=\frac{h}{1892} \rightarrow h = 1892 \tan (16^o32') \approx 562ft\]to nearest foot.

Answer 2

i cant see the rest

Answer 3

Refresh your screen. It should all be visible.