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\[4\ln (\sqrt{x})+6\ln (x ^{1/3})\]
i dont know how to simplyfy this
\[4\ln \sqrt{x}+6 \ln x^{1/3}=4 \times \frac{1}{2}\ln x+6 \times \frac{1}{3}\ln x\]
\[=2 \ln x + 2 \ln x = 4 \ln x\]
thanks
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