Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

A ball is thrown upward from a 100-foot tall building with an initial velocity of 14 feet per second. Its height s(t) is given by the function s(t) = -16t squared + 14t +100. Find the interval of time for which the ball is greater than 103 feet.

OpenStudy (anonymous):

\[t0 = 3/8, t1 = 0.5\]

OpenStudy (anonymous):

just solve for the height equation when it's greater than 103ft, that's -16t^2+14t+100>103 ---> 3/8<t<1/2, as locorider said

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!