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OpenStudy (anonymous):
would this be right?? 360-70 degrees.. to find the probability that a point chosen at random is in the figure..
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
is the question to find the probability that a randomly chosen point would be in the "shaded part" of the circle?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
70/360=0.194
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OpenStudy (anonymous):
okay thank you
OpenStudy (anonymous):
you're welcome
OpenStudy (anonymous):
That could be your probability as a decimal number. What unit or form is the solution to your problem required in? A decimal or a percentage?
OpenStudy (anonymous):
it doesnt say
OpenStudy (anonymous):
what would it be in %?
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OpenStudy (anonymous):
0.194 x 100 = 19.4%
OpenStudy (anonymous):
okay thank you
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