Question

Please help me,
simplify, leave in exponent form
5(rt)^9

Answer 1

Expand, then simplify. Eventually you'll be able to do the simple way, but for now lets keep with the basics.

Answer 2

If you want to have someone check your answer please post the answer you got and ask for a check. Just posting the problem makes it appear as though you're not doing the work or understanding the material which makes people tend to not want to continue helping. If you show that you've done it and you just want to be sure you're correct people are more than happy to confirm.

Answer 3

so r*r*r*r*r*r*r*r*r
t*t*t*t*t*t*t*t*t

Answer 4

i still dont understand i get some of the problems but a few of them like this and the last I just cant figure out

Answer 5

It's ok. you're doing really well.
\[5(rt)^9 = 5(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)(rt)\]
\[=5rrrrrrrrrttttttttt\]
Right?

Answer 6

yes so 5r^9t^9?

Answer 7

yes.

Answer 8

yayyy, can you explain the FOIL method to me?

Answer 9

Sure. You know that
a(b+c) = ab + ac
Right?

Answer 10

yes so like (3x-6)(x-12)

= 4x+18

Answer 11

That's jumping ahead, and not quite correct. Lets back up a step.

Answer 12

haha ok sorry

Answer 13

4(x + 3) = ?

Answer 14

4x+12?

Answer 15

Right.
But we know that 4 is 3 + 1, so we should get the same thing if we rewrite it as
(3+1)(x+3)

Answer 16

So lets take that whole first factor and multiply it by each of the terms in the second factor
\[ \rightarrow (3+1)(x+3) = (3+1)x + (3+1)3\]

Answer 17

And then we distribute again..
\[(3+1)x+(3+1)3 = 3x + 1x + 9 + 3\]

Answer 18

\[ = 4x+12\]

Answer 19

sorry had to step away for a moment

Answer 20

=4x+12?

Answer 21

So now if we have something like:

(a+b)(c+d) we can distribute:

\[(a+b)(c+d) = (a+b)c + (a+b)d = ac + bc + ad + bd\]

Answer 22

But to make it easy to remember they prefer you to use FOIL which does the same thing, but in a different order.

Answer 23

+bd

Answer 24

i have like 5 sections and the first says use the foil and the rest just says find the product

Answer 25

(a+b)(c+d)
They take the
F irst two terms(a and c)
O uter two terms(a and d)
I nner two terms (b and c)
L ast two terms (b and d)

ac + ad + bc + bd

Which is the same as what we had, but with a slightly different order.

Answer 26

oh okay im going to work a problem really quick can you check my answer?

Answer 27

yep

Answer 28

(3x-6)(x-12)

4x+3x-12-6x+18

Answer 29

Afraid not.

(3x-6)(x-12)

Multiply the
F irst two terms (3x and x)
3x * x = ?

Answer 30

4x

Answer 31

Nope.

4x = 3x + x

Answer 32

3x^2

Answer 33

Correct.

Now the
I nner two terms (-6 and x)

-6 * x = ?

Answer 34

-6x

Answer 35

Now the
O uter two terms(-6 and -12)

-6 * -12 = ?

Answer 36

72

Answer 37

Blah! Those are not the outer terms, they're the Last terms. Sorry.

Answer 38

Now the
O uter two terms(3x and -12)

3x * -12 = ?

Answer 39

is it -36x? or does it say the same since they are not like terms?

Answer 40

it is -36x, just like -6 * x was -6x.

Answer 41

You can rearrange the factors of a product.

a*b*c = a*c*b = b*c*a = c*a*b = ... etc

Answer 42

so now i have:
3x^2-6x^36x+72?

Answer 43

yes, except that it's -6x-36x, not -6x^36x but I think that was a typo.

Answer 44

yes sorry so now it is 33?

Answer 45

-6-36 = ?

Answer 46

-42

Answer 47

so
-6x-36x = x(-6-36) = ?

Answer 48

x(-42)

Answer 49

So

\[ 3x^2 - 6x - 36x - 72 = ?\]

Answer 50

i thought i had the answer, im never going to get through college :(

3x^2-x(-42)-72

Answer 51

You're really close. The only problem is you left an extra - there.

Answer 52

before 72?

Answer 53

We said that -6x-36x = x(-42)
which we can re-arrange to be -42x

So 3x^2 -6x -36x - 72 = 3x^2 -42x - 72

Answer 54

ohh man im never going to pass, im sorry you had to take your free time to help me. thank you so much im just having the hardest time

Answer 55

no you're doing great

Think about it like this. If you have 4x's and you subtract 36x's you'll be at -32x's right?

Answer 56

right

Answer 57

everytime i think i get it a new problem comes up and im so lost again

Answer 58

so if you have -6x's and you take away 36x's you'll be at -42x's

Answer 59

That's ok. New problems should challenge you. Otherwise you'd just be doing things you already know and you wouldn't learn anything.

Answer 60

yes your right, im just frustrated if i cant get this how am i supposted to get the next two classes