In solving the system -4x + 6y = -1 and -x + 1.5y = 0, Sue arrived at the equation 0 = -1 . Assuming Sue did not make a mistake, that means the system has:

a. (0, -1) as its only solution
b. infinitely many solutions
c. no solution
d. (-1, 0) as its only solution
e. has (0, -1) and (-1, 0) as its only solutions

Question

In solving the system -4x + 6y = -1 and -x + 1.5y = 0, Sue arrived at the equation 0 = -1 . Assuming Sue did not make a mistake, that means the system has:

a. (0, -1) as its only solution
b. infinitely many solutions
c. no solution
d. (-1, 0) as its only solution
e. has (0, -1) and (-1, 0) as its only solutions

anonymous · Answer

when solving for the unknown variable you will get three possible answers

anonymous · Answer

if solving for x and you get x= something, the you have an exact solution ( one solution)

anonymous · Answer

if solving equations and your variables drop out and you get a true statement I.E 0=0, then you get infinite solutions.

anonymous · Answer

if you are solving the equation and the variables drop out and you get a false statement, I.E 1=2, then you have no solutions.

anonymous · Answer

thank you