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Solve the system 2x - 3y = 0 and x + 4y = -11 by graphing each line
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Graph both of them wherever they intersect the x and y coordinates are your answer :D
numerically if you want to check your answer you can use substitution method. so 2x = 3y and x = 3y/2 so then 3y/2 + 4y = -11 so 3y/2 + 8y/2 = 11y/2 = -11 so 11y = -22 and y = -2 so then x = 3(-2)/2 = -3
so (-3,-2) is where the two lines would intersect
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