Question

Prove that the triangles are similar. http://i1116.photobucket.com/albums/k562/Leng321/Untitled.jpg

Answer 1

<ADB = < BDC (both =90°)

<DAB+<ABD = 90° (sum of triangle = 180°)
and <ABD+<DBC=90° (given)
so <DBC = <DAB

so triangle ADB ~ triangle BDC (because of AA~ or AAA)

Answer 2

oh my gosh, thank you. that was so simple. i spent so much time on this, ha

Answer 3

You're most welcome ^o^