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In solving the system -4x + 6y = -1 and -x + 1.5y = 0, Sue arrived at the equation 0 = -1 . Assuming Sue did not make a mistake, that means the system has: a. (0, -1) as its only solution b. infinitely many solutions c. no solution d. (-1, 0) as its only solution e. has (0, -1) and (-1, 0) as its only solutions
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0 = -1?? That doesn't make any sense.. right? so (C) no solution
Right. Thank you.
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