Question

4^-2+2*3^-2

Answer 1

\[4^{-2}+2\times3^{-2}=\frac{1}{4^2}+2 \times \frac{1}{3^3}=\frac{1}{16}+\frac{2}{9}=\frac{9+16 \times2}{16 \times 9}=\frac{41}{144}\]

Answer 2

\[=\frac{41}{144}\]in case the site cut the answer off above. Just remember what the minus sign on the exponent does - \[a^{-n}=\frac{1}{a^n}\]