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how to integrate 1/(xlnx)?
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i'm trying to do it in parts, u=lnx and dv=x^(-1)dx
but then i can't get v
Let u = ln(x) du = 1/x dx => dx = xdu.
plug that in and ull get a simple int 1/u du =]
oh that's not even parts, that's just a simple substitution. wow, didn't see that there! thank you!
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