Question

(x+2)/(x^2+6x-7)=8/(x^2+3x-4)

Answer 1

you want to solve for x? :)

Answer 2

simplify? :)

Answer 3

If it's simplification then factor first and you'll get:\[= [(x+2)/(x+7)(x-1)] - [8/(x-1)(x+4)]\]

multiply by x +7 and x+4 to get the same denominator :
\[= [(x+2)(x+4)-8(x+7)/(x-1)(x+7)(x+4)]\]

\[= (x^2 -2x - 48)/(x-1)(x+7)(x+4)\]
\[= (x-8)(x+6)/(x-1)(x+7)(x+4)\]

That's it ^_^