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Could you show me how to reduce these algebraic fractions and then multiply?
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\[2a ^{2}-7a - 15 \over 3a ^{2} - 8a -3\] times \[9a ^{2} - 1 \over 4a ^{2} - 9\] times \[2a ^{2} - 9a + 9 \over a ^{2} + 3a -10\]
(2a ^{2}-7a-15)/(3a ^{2}-8a-3) =(2a+3)(a-5) /(3a+1)(a-3)
(9a^2-1)/(4a^2-9)= (3a+1)(3a-1)/(2a+3)(2a-3)
outcastlilgurl, factorise the numerator and the denominator for those three fractions, then you try to cancel any similar factors
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