How to find the maximum, the minimum and the x-intercepts in the interval (-2pi, 2pi)? The equation is y=3 cos x/2

Question

How to find the maximum, the minimum and the x-intercepts in the interval (-2pi, 2pi)?  The equation is y=3 cos x/2

anonymous · Answer

r u gettin help?

anonymous · Answer

I have not received any help yet.  I would really appreciated it because I am struggling with finding how to solve this problem

anonymous · Answer

the x-intercepts occur when y=0. so u set the equation to equal zero then solve for x. so x=2*arcos (0). then u differentiate the equation to get dy/dx = -3/2sin(x/2). then set this to equal zero and solve for x. then put your ans into the original function to solve for y. this gives u ur max and min value