2/3x+4/3x=-2/3
alright, let's simplify it in a better form ^_^:\[2/3x(2x+4) = -2/3\] cross mulitply now: \[-6x(3x + 4)= 6\] \[-6x(3x+4) - 6 = 0\]\] \[-6(3x^2 + 4x +1 ) = 0\] \[-6(3x + 1)(x + 1) = 0\] so your zeros are : x = -1/3 and x= -1 ^_^
is it clear now? :)
so the answer is 0
no lol, you want to find x right?
yes sorry about its early
np ^_^ so you'll have 2 sets of x equations which are: 3x + 1 =0 and x+ 1 =0 x = -1/3 and x = -1 therefore your x's are : x = -1/3 and x = -1
oh ok got it ... thank you!
you'r welcome :)
you're* ^^"
can't I have one day with no typos =-=
sstarica, you are such a good person that I cant even believe it, I mean, you spend your precious time helping others
thank you andy, I appreciate such kind words :)
sstarica do have time for one more problem?
sure np ^_^
0.06(z-300)+0.05z=0.07z-205
First, let's multiply using the distributive law :\[0.06z - 18+0.05z -0.07z + 205 = 0\] Solve for z and you'll get: \[0.04z = -187\] \[z = -187/0.04 = -4675\] so z = -4675 ^_^
how did u get the 187
you subtract 205 from 18: 205 - 18 = 187 move it to the other side to get z alone and it'll be -187 ^_^
ok got it
great :)
thank you , you are really good at this ..thanks again
it's my pleasure dear ^_^ good luck
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