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OpenStudy (anonymous):
Integrate:
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OpenStudy (anonymous):
\[\int\limits{\sqrt{4x+1}} dx \]
OpenStudy (anonymous):
the answer is \[(1/6)[(4x+1)^{3/2}]\] set u = 4x + 1 and du = 4dx \\[1/4\int\limits\limits\limits_{}^{}(u ^{1/2)^{}}du\]
OpenStudy (anonymous):
cheers
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