solve the polynomial equation. in order to obtain the first root, use synthetic division to test the possible rational roots. x^3+6x^2+21x+26=0

Question

amistre64 · Answer

possible roots are what; factors of 26/factors of 1?

anonymous · Answer

yes

amistre64 · Answer

1,26 ; 2, 13;  cant think of any more :)  make em +- of course

amistre64 · Answer

2 | 1  6  21  26
     0  2  16
    -----------
     1  8  ... doesnt seem to be a root.....

amistre64 · Answer

-2 | 1   6   21   26
       0  -2  -8  -26
     --------------
       1    4  13     0  .... x = -2 is a root  i think

amistre64 · Answer

(x+2)(x^2 +4x +13)

amistre64 · Answer

thats all she wrote on that one,  the quadratic doesnt touch the x axis so no more roots allowed

amistre64 · Answer

do you agree?  or wanna know how i did it?

anonymous · Answer

sorry.....I agree