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OpenStudy (anonymous):
find the average value from -1 to 1 of f(x)=2x
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OpenStudy (anonymous):
i think this is the mean value for integral: 1/(b-a) \int_a^b f(x) dx
OpenStudy (anonymous):
yeah, that is it.
OpenStudy (anonymous):
assuming a^b means a and b are the bounds of integration
OpenStudy (anonymous):
i find the answer is 0, is it correct ?!?
OpenStudy (anonymous):
yup, it is 0
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OpenStudy (anonymous):
yeah, that is right. and makes sense given that it is an odd funtion you are integrating
OpenStudy (anonymous):
what about ODD or EVEN, i don't get it, please explain, thanks
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