Solve the integral (sin^2(x)*cos^2(x)) dx / (sin^8(x) - cos^8(x)) .

Question

anonymous · Answer

is your dx supposed to be part of the numerator or you typed that wrong?

anonymous · Answer

it's regular dx, after everything

anonymous · Answer

so it's supposed to be $$(\sin ^{2}x \cos ^{2}x/\sin ^{8}x-\cos ^{8}x) dx?$$

anonymous · Answer

6 inches in diameter, 5inches in height, what is the total number of cubic inches. please help what am I doin wrong. 3.14*3squared*5* I don,t know what o do next

anonymous · Answer

presidential you can't just hijack his thread. start your own please.

anonymous · Answer

sin^8x-cos^8x is together in the denominator

anonymous · Answer

This one is kinda complicated so I'd like you to go here http://www.wolframalpha.com/input/?i=integrate+%28sin^2xcos^2x%2F%28sin^8x%E2%88%92cos^8x%29%29dx Hope that helps you out.