Mathematics
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OpenStudy (anonymous):
Find the slope of the tangent line to the curve 2x^4-3x^2+sq.x-5/x^2 at point (1,-5)
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OpenStudy (amistre64):
is the x^2 the denominator of everything else?
OpenStudy (anonymous):
no just the denominator of 5
OpenStudy (amistre64):
ok...so the last term is 5/x^2 everything else is as is..
OpenStudy (anonymous):
i was thinking about rewriting it as 5x^-2, but i'm not sure
OpenStudy (anonymous):
correct
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OpenStudy (amistre64):
go ahead, its all good :)
OpenStudy (anonymous):
ook cool
OpenStudy (amistre64):
8x^3 -6x +(1/2sqrt(x)) +(10/x^3) is what i get... maybe its right?
OpenStudy (anonymous):
yea i got 8x^3-6x+1/2x^-1/2-10x^-3, should i substitute after this?
OpenStudy (amistre64):
yep, but I think you only need the "x" value
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OpenStudy (amistre64):
8 -6 + (1/2) +10
OpenStudy (anonymous):
yea so just substitute the x value
OpenStudy (amistre64):
and youve got a typo,,,that last term should be a (+); -5(-2)=10
OpenStudy (anonymous):
oh yea thanks
OpenStudy (amistre64):
I get 6 as the slope... if I did it right :)
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OpenStudy (anonymous):
uhm i'm not sure if we're doing it right cuz the problem is actually asking me for the equation of the line
OpenStudy (amistre64):
the derivative is the equation of the slope of the line; or maybe it should be in y = mx+b format?
OpenStudy (anonymous):
yea i think that's what they mean y=mx+b format
OpenStudy (amistre64):
y = 6x +b at (x=1,y=-5)??
-5 = 6(1) + b
-5 = 6 + (-11)
y = 6x-11 then
OpenStudy (anonymous):
hold up, how did u get 6 as the slope, i'm up to 8-6+1/2+10
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OpenStudy (amistre64):
f'(x) = m
8-6=2+10=12...ahhh, I see; I multiplied by 1/2
OpenStudy (amistre64):
12.5 happy :)
OpenStudy (anonymous):
ook cool
OpenStudy (anonymous):
lol
OpenStudy (amistre64):
-5 = 12.5(1) + b
-5 -12.5 = b
-17.5 = b
y = 12.5 - 17.5...
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OpenStudy (amistre64):
squeeze an "x" right up next to that 12.5
OpenStudy (amistre64):
or do they want it in Ax + By = C format?
OpenStudy (anonymous):
y=mx+b format
OpenStudy (amistre64):
you can use the line equation to figure out a new "x value" when iterating a function solve it...
OpenStudy (anonymous):
uhm not sure about that... does that mean that y=6x-11 is not it
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OpenStudy (amistre64):
yeah, since i miscalculated the first time with a "6", its a bad apple...toss it out before it spoils the rest :)
OpenStudy (anonymous):
ook
OpenStudy (anonymous):
ok then it's 8-6+1/2+10=12+1/2=25/2
OpenStudy (anonymous):
so the slope is 25/2
OpenStudy (anonymous):
got it thanks :)