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Mathematics 9 Online
OpenStudy (anonymous):

write as a perfect cube: 64z^6

OpenStudy (anonymous):

what * what * what = 64?

OpenStudy (anonymous):

what about the z^6

OpenStudy (anonymous):

What is the number first?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

OK (4z )^3 Since we are going to have a power to a power on the z term... You take the 6 and divide by 3 = 2 SO (4z^2)^3

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