Question

Solve the following equation.Describe solution set as contradiction, identity, or conditional.

3(6-x)+2x=14+4(x-1)-5x

Answer 1

Contradiction. Expand the left-hand side:

18-3x+2x = 18 - x

Now expand the right-hand side:

14 + 4x - 4 - 5x = 10 -x

Compare the LHS with RHS:

\[18-x=10-x\]add x to both sides and you get\[18=10\]which is a contradiction.