Question

The lengths of the sides of a triangle are 8, 11, and 14. Find the perimeter of a similar triangle whose longest side measures 21.

Answer 1

\[\frac{O_2}{O_1}=\frac{a_2}{a_1}=\frac{b_2}{b_1}=\frac{c_2}{c_1}=\frac{21}{14}=1.5\]
\[O_2=1.5O_1=1.5(8+11+14)=49.5\]

Answer 2

can u explain to me how you got that ?

Answer 3

These triangls are similar. Similarity ratio is 21/14=1.5. Their perimeters are similar also.

Answer 4

where did u get 1.5 ?

Answer 5

where did u get that equation ?

Answer 6

longest side of 2nd triangle : longest side of 1st triangle = 21:14 =1.5

Answer 7

oh i understand now. thanks