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Mathematics 9 Online
OpenStudy (anonymous):

At a high school cafeteria, diners can choose one vegetable from a choice of 2 vegetables, one meat from a choice of 2 meats, one serving of bread from among 3 breads, and a dessert from among 3 desserts. How many meal configurations are possible? A.10 B.36 C.4 D.12 E.18

OpenStudy (gg):

B

OpenStudy (gg):

u choose a vegetable on 2 ways, meat on 2, bread on 3 and dessert on 3. The number of choices is 2*2*3*3=36

OpenStudy (anonymous):

OH ok Thanks that's easy enough I was way over thinking that one lol

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