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Mathematics 13 Online
OpenStudy (anonymous):

Quick Trig Help... Need help understanding a small point!

OpenStudy (anonymous):

\[16\sqrt{2}(1-i) = 32(1/\sqrt{2}-i/\sqrt{2})=32(\cos (\pi/4)+isin(\pi/4))\] I get all of it APART from the + isin(pi/4), where did the "+" come from? Thanks!

OpenStudy (anonymous):

=32(cos(π/4)+isin(π/4)) Last part seems to have cut off...

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