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OpenStudy (anonymous):
how do you solve (18-n)^1/2=(n/8)^1/2
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OpenStudy (anonymous):
=> sqrt(18-n)=sqrt(n/8) => 18-n=n/8 =>18= n/8+n => 9n/8 =18 => n = 18*8/9
OpenStudy (anonymous):
because to the power 1/2 is actually square root
OpenStudy (anonymous):
what do you have to do with both the 1/2
OpenStudy (anonymous):
x^(1/2)=sqrt(x) understand now ?
OpenStudy (anonymous):
a little =) im looking over the answer just to see how you did it
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