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Mathematics 26 Online
OpenStudy (anonymous):

√3:(sin^2x) using the chain rule

OpenStudy (anonymous):

can somebody help me find the cubic root of sin^2x

OpenStudy (anonymous):

sin^(2x*1/3) = sin^(2/3x)

OpenStudy (anonymous):

whatttt

OpenStudy (anonymous):

please explainnn

OpenStudy (anonymous):

the cubic root of say X is actually X ^(1/3) you just plug in and you get what I wrote

OpenStudy (anonymous):

do you get it ?????????????????

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

the answer i get is 2(cosx) / 3(sin^(1/3) x

OpenStudy (anonymous):

are u deriving it or what ?

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