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OCW Scholar - Physics II: Electricity and Magnetism 12 Online
OpenStudy (anonymous):

Semiconductor question. Please solve question 29 in the diagram attached. The answer is B.) Please show all the steps.

OpenStudy (anonymous):

The no. of atoms in the intrinsic semiconductor is \[2 * 10^{28}\] atoms/ \[m ^{3}\]. The no. of electrons before doping was \[2 * 10^{16}\] / \[m ^{3}\]. The answer is \[2 * 10^{10}\].

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