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is x^2-7x-8 factorable?
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(x-8)(x+1)
ohh duuhh haha
it goes along with your other problem therefore (x-8)s will cancel out
yeah they will also is x^2-1 factorable?
its (x-1)(x+1)
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just expand it to x^2 + 0x + 1 its easier to factor that way
i dont get that my teacher only taught us how to factor with 3 or more terms
oh ok thanks
no problem
i've cancelled the x-8 and the x+1 in my problem and now i have ((1)/(3x))X((4x^3)/(x-1)) is that simplified?
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yeah that is the most simplified it can get
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