Find the period of the function. I REALLY need HELP!

y= sec(2x+(3pi/2))
y= -4csc(3x+4)
y=6tan(x-(pi/4))
y= 5sec(4pi(x))
y= tan(1/3(x+(pi/4))
y= tan(1/7x)
y= 3csc(x-(pi/3))
y= 10tan((pi/2)x)
y= 2cot x
y= csc(5(x+(pi/5))
y= csc(1/8x)
y= 7csc(x+(pi/2))

Question

Find the period of the function. I REALLY need HELP!

y= sec(2x+(3pi/2))
y= -4csc(3x+4)
y=6tan(x-(pi/4))
y= 5sec(4pi(x))
y= tan(1/3(x+(pi/4))
y= tan(1/7x)
y= 3csc(x-(pi/3))
y= 10tan((pi/2)x)
y= 2cot x
y= csc(5(x+(pi/5))
y= csc(1/8x)
y= 7csc(x+(pi/2))

amistre64 · Answer

the period of all the functions?

amistre64 · Answer

2pi/2
2pi/3
 pi
2pi/4
3pi..... like that

amistre64 · Answer

sin(____ x.....)
       ^^
     this number here modifies your normal period

Whatever it is, multiply its reciprocal by the normal period of the function...

anonymous · Answer

I actually understand this thanks to you. I aced my hw :)

amistre64 · Answer

yay!!   :)