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is the answer to q: y+6=17/10(x+4) a:17/10x+11
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Does the equation look like this: \[6+y==\frac{17 (4+x)}{10} \] or this: \[6+y==\frac{17 }{10(4+x)} \] In either case, to solve each equation for y add a -6 to each side of the equations and simplify as desired. \[y=\frac{1}{10} (8+17 x) \text{ and } y=\frac{-223-60 x}{10 (4+x)} \text{ respectively}\]
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