Question

dy/dx x^2y^2+xy=2

Answer 1

hi try D(uv)=uDv+VDu

Answer 2

D(x^2 y^2)+D(xy)=D2

Answer 3

did u get it now kels?

Answer 4

(x^2)2yy'+(y^2)2x + xy'+y=0

Answer 5

now collect the dy/dx=y'

Answer 6

2y(x^2)y'+xy'=-2x(y^2)-y

Answer 7

y' (x^2 +x)= -2x(y^2)-y

Answer 8

y'=dy/dx= [-2x(y^2)-y]/(x^2 +x)

Answer 9

i think thats the final answer kels? did u get it how we get it from there?

Answer 10

thats exactly what i got, it just didn't seem right to me lol thank you! (: