Equation: 10(x-1)(x-2)(x-3)=1 has three real solutions a

Question

Equation: 10(x-1)(x-2)(x-3)=1 has three real solutions a<b<c find A,B,C
Hint: ask what the solutions are if the right hand side is 0 instead of 1, and use Newton's Method

radar · Answer

Using the Hint, I say self what would be solution if the 1 on the right was a 0?.  Well 10 is 10 so one or two or may be all three of the remaining factors are o, then

x=1, x=2, x=3   But it isn't a zero, it is 1 on the right.  So now what do I do?

anonymous · Answer

i truly have no clue how tho do this problem

radar · Answer

As you may have guessed, I don't either....If it was a zero on the right!  I think I could.lol