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not sure if this question went through. y+x=-8 what is the y-intercept? write in ordered pair form. (0,-8) is that correct? Thank you
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Yes.
when x = 0 the only place for the line to go is somewhere along the y axis, the intercept. and yes, when x = 0, the only option for y is to be -8
right, like amistre64 said, but perhaps I can frame it better, no disrespect to amistre64: y-axis | | | | | ---------------------------------------x-axis It is the point where your line(determined by your equation) INTERCEPTS the y-axis. Hence, it is called the y intercept. so, along the y axis, x is 0. so if you want to find out the y-intercept of your equation, just plug x = 0 in the equation.
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