what is the area and width of a triangle with the measures of 29.6=21+2w

Question

amistre64 · Answer

i take it that that is the perimeter of the triangle in question...

anonymous · Answer

yes

amistre64 · Answer

make s = the area is half the perimeter

then use Herons formula

sqrt(s(s-a)(s-b)(s-c)) = area.   if I remember it correctly

amistre64 · Answer

that 2w seems a bit off, I would assume that means that 2 of the legs are of equal length and that they measure "w" in length

amistre64 · Answer

maybe it means after you find the area, use what you know for "w" to plug into the normal area formula.

Area = width(height)/2

anonymous · Answer

can you answer this one.....
what is the area and width of a rectangle with the perimeter of 29.6 and the length of 10.5..? i used P=2l+2w but i dont know how to solve it

amistre64 · Answer

29.6 - 21 = 8.6

which dont make no sense,  side thats 21, you would need 2 more sides that add up to at least 21.  All thats left here is 17.2.

Im thinking that either theres imformation missing or that this dont make a triangle

amistre64 · Answer

but then again, im using my georgia math....

anonymous · Answer

well can you answer this...
Use P=(2)l+(2)w
so far I have 20.6=(2)l+(2)3.1
can you solve that so i know the width?