Question

A bone that originally contained 150 mg of carbon-14 now contains 85 mg of that isotype. Determine the approximite age of the bone, if the half-life of carbon-14 is 5570 years. Help please!!! Hint: Use this formula: A=A(subscript 0)2^(t/k)

Answer 1

the actual formula is
\[A=A_02^{\left(-\frac{t}{k}\right)}\]
here given A=85, Ao=150, k = 5570, find t

by solving, we get
t = 4564.2 years